Subject: Re: [xsl] Escaping Characters in replace() From: Nathan Tallman <ntallman@xxxxxxxxx> Date: Tue, 15 Oct 2013 12:44:29 -0400 |
Thank you, David. Unfortunately, I still get ". after processing... (I'm transforming XML to HML, btw.) Also, a question. Why didn't you need to escape the period in the third argument of replace()? (When I inert one, my processor throws an error; so, I understand it's wrong, but not why. Also, I seem to be able to delete the backslash in front of the period in the second argument without causing problems... Why is that?) On Tue, Oct 15, 2013 at 12:23 PM, David Carlisle <davidc@xxxxxxxxx> wrote: > On 15/10/2013 17:22, David Carlisle wrote: >> >> On 15/10/2013 17:13, Nathan Tallman wrote: >>> >>> I'd like to search for all occurrences of ". and replace them with ." >> >> >> >> . is special to regex but " is not so you want >> >> replace(.,'"\.','."') >> >> Then for XSLT you need to get that into an XML attribute, so if you use >> " for the attribute delimiter you need "' for the " in the >> attribute, so >> >> <xsl:value-of select="replace((.,'"\.','."')"/> > > just one ( here > >> >> >> David >> > > > -- > google plus: https:/profiles.google.com/d.p.carlisle > > ________________________________________________________________________ > The Numerical Algorithms Group Ltd is a company registered in England > and Wales with company number 1249803. The registered office is: > Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. > > This e-mail has been scanned for all viruses by Star. The service is > powered by MessageLabs. > ________________________________________________________________________
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