Subject: Re: [xsl] How to do macro substitution in XPath? From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sat, 2 Dec 2023 18:12:18 -0000 |
> Here is the wanted "pure XPath" that preserves the "readability": > > let $LBJ := /Book/Title eq 'Path to Power' and /Book/Author eq 'Robert A. Caro', > $RM := /Book/Title eq 'Power Broker' and /Book/Author eq 'Robert A. Caro' > return > if($LBJ) then 'action 1' > else if($RM) then 'action 2' > else 'Error' > The disadvantage here is that the code doesn't have a high level of reusability. The code as written can only be used to test a book element that is the outermost element of the current document. I prefer to use functions: let $LBJ := function($book as element(Book)) as xs:boolean {$book/Title eq '....' and $book/Author eq '....') let $RM := function(....) return if ($LBJ(/Book)) then 'action 1' else if ($RM(/Book)) then 'action 2' ... But although an XPath expression was requested, the context appears to be XSLT, and in that case I would use good old template rules: <xsl:template match="Book[Title eq 'Path to Power' and Author eq 'Robert A. Caro']"> action-1 </xsl:template> <xsl:template match="Book[Title eq 'Power Broker' and Author eq 'Robert A. Caro']"> action-2 </xsl:template> Michael Kay Saxonica
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