Something to ponder...

[David Megginson <dmeggins@xxxxxxxxxx>]

Here's a nice problem for the more abstract-minded DSSSL enthusiasts
among you.

Assume that I have three singleton node-lists, "a", "b", and "c".

I append the lists using the `node-list' primitive, but in different
orders:

  (let ((nl1 (node-list a b c))
        (nl2 (node-list b c a)))
    ...)

Clause 10.1.2 states that `node-list=?' "returns #t if nl1 and nl2 are
the same node-list, that is, they contain the same members in the same
order, and otherwise returns #f."  Given that definition, the
following query should obviously return #f:

  (node-list=? nl1 nl2)

But it's not clear (at least, not to me) what this query should
return:

  (node-list=? (node-list-no-order nl1) (node-list-no-order nl2))


All the best,


David

--
David Megginson                 ak117@xxxxxxxxxxxxxxxxxxx
Microstar Software Ltd.         dmeggins@xxxxxxxxxxxxx
University of Ottawa            dmeggins@xxxxxxxxxx
        http://www.uottawa.ca/~dmeggins