Subject: Re: Something to ponder... From: James Clark <jjc@xxxxxxxxxx> Date: Wed, 23 Apr 1997 13:41:48 +0700 |
At 17:28 22/04/97 -0400, David Megginson wrote: >Here's a nice problem for the more abstract-minded DSSSL enthusiasts >among you. > >Assume that I have three singleton node-lists, "a", "b", and "c". > >I append the lists using the `node-list' primitive, but in different >orders: > > (let ((nl1 (node-list a b c)) > (nl2 (node-list b c a))) > ...) > >Clause 10.1.2 states that `node-list=?' "returns #t if nl1 and nl2 are >the same node-list, that is, they contain the same members in the same >order, and otherwise returns #f." Given that definition, the >following query should obviously return #f: > > (node-list=? nl1 nl2) > >But it's not clear (at least, not to me) what this query should >return: > > (node-list=? (node-list-no-order nl1) (node-list-no-order nl2)) An implementation may legally return either #t or #f (but not anything else) in this case. James
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