Subject: RE: [xsl] How to sort a nodeset referenced by a variable? From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 05 Jul 2001 12:04:50 +0100 |
I changed the sort key from <xsl:sort select="$fileterNode/secondElement"> to <xsl:sort select="./secondelement" />
It started working. I think now I understand your point.
Cheers, Wendell
Hi Mike, Thanks for the response I got it working.
I changed the sort key from <xsl:sort select="$fileterNode/secondElement"> to <xsl:sort select="./secondelement" />
It started working. I think now I understand your point.
regards, Shailendra
On Wed, 4 Jul 2001, Michael Kay wrote:
> > I am doing something like this
> >
> > <xsl:variable name="filterdNode" select="//*" />
> >
> > <xsl:variable name="sortedList">
> > <xsl:for-each select="$filterNode/someElement">
> > <xsl:sort select="$fileterNode/secondElement">
>
> The value of your sort key will be the same for every node in the
> collection. It's meaningless to use a sort key whose value doesn't depend on
> the context node.
>
> Mike Kay
> Software AG
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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