[xsl] position within same nodes

Subject: [xsl] position within same nodes
From: Laurence O Garfield <lgarfiel@xxxxxxxxxxxxxxxxxxx>
Date: Thu, 19 Jul 2001 13:35:10 -0500 (CDT)
What is the XPath to get the position of a given node relative to its
siblings of the same name?  Eg,


I'm looking for an XPath statement that would return 1 for the first meep,
2 for the second, and 3 for the 3rd meep, rather than 2, 3, and 5 (which
is what plain position() returns).

I'm trying to count the number of siblings and subtract the number of
siblings of the same type, then subtract that from position(), but I can't
get either of the first two parts there to work either.  Does anyone have
any suggestions?

--Larry Garfield

-- "If at first you don't succeed, skydiving isn't for you." :-)

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