Re: [xsl] position within same nodes

["Thomas B. Passin" <tpassin@xxxxxxxxxxxx>]

Stylesheet:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">
    <root>
        <xsl:variable name='meeps' select='//meep'/>
        <xsl:for-each select='$meeps'>
         <xsl:value-of select='position()'/>--
        </xsl:for-each>
    </root>
</xsl:template>
</xsl:stylesheet>


Results:

<root>1--
  2--
  3--
  </root>


Cheers,

Tom P

[Laurence O Garfield]

> What is the XPath to get the position of a given node relative to its
> siblings of the same name?  Eg,
>
> <blah>
>  <argh/>
>  <meep/>
>  <meep/>
>  <stuff/>
>  <meep/>
> </blah>
>
> I'm looking for an XPath statement that would return 1 for the first meep,
> 2 for the second, and 3 for the 3rd meep, rather than 2, 3, and 5 (which
> is what plain position() returns).



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