Re: [xsl] for-each order

[Trevor Nash <tcn@xxxxxxxxxxxxx>]

>Caveat: I'm a relative newbie, still weaning myself off disable output
>escaping....
>
Keep at it!  ;-))

>There are a variety of ways of reversing things - just search on the archive
>for reverse, or see
>http://sources.redhat.com/ml/xsl-list/2001-08/msg00243.html
>
>but in this particular case I'm thinking that this (untested) might work:
>
> <xsl:variable name="position">
>    <xsl:for-each select="$path">
>	  <xsl:sort order="descending" select="position()"/>

Very close.  The data-type="number" is important, otherwise item 10
sorts next to item 1.

>       <xsl:value-of select="@value"/>,
>    </xsl:for-each>
> </xsl:variable>
>
>David.

Regards,
Trevor Nash
--
Traditional training & distance learning,
Consultancy by email

Melvaig Software Engineering Limited
voice:     +44 (0) 1445 771 271 
email:     tcn@xxxxxxxxxxxxx

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list