Subject: [xsl] order-by: char or int? From: "TP" <tpass001@xxxxxxxxxxx> Date: Fri, 14 Dec 2001 13:40:28 -0600 |
My xsl:for-each looks like this <xsl:for-each select="PrintCabinate/item" order-by="+ Name;currentPage"> ---- </xsl:for-each Now while sorting it, it assumes that currentPage is char, so it places 11 before 7 for eg, whereas 7 shud be b4 11. is there a way to convert currentPage to int for the purpose of sorting. Thanks in advance. TP XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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