Re: [xsl] position() seems always to be 1

Subject: Re: [xsl] position() seems always to be 1
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 27 May 2003 11:36:56 +0100

	  	<xsl:when test="self::node()[position()=last()]">

The self axis selects a set of at most 1 node, so when that set is ordered
into document order, the position of the node in the resultimg node list
will always be one.

This is a FAQ. position() is not a property of the node in the source
tree it is a property of the current node list, that is, roughtly
speaking,  the nodes most recently selected by a select attribute

If the select attribute on teh apply-templates that is active at this
point only slects the nodes that you are interested in (not other
element or text nodes) then you can just do

<xsl:when test="position()=last()">

otherwise you don't want position at all, you just want to know if there
is (for example) no following-sibling download element which would be

<xsl:when test="not(following-sibling::download)">


This e-mail has been scanned for all viruses by Star Internet. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:

 XSL-List info and archive:

Current Thread