Subject: Re: [xsl] position() seems always to be 1 From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 27 May 2003 11:36:56 +0100 |
<xsl:when test="self::node()[position()=last()]"> The self axis selects a set of at most 1 node, so when that set is ordered into document order, the position of the node in the resultimg node list will always be one. This is a FAQ. position() is not a property of the node in the source tree it is a property of the current node list, that is, roughtly speaking, the nodes most recently selected by a select attribute If the select attribute on teh apply-templates that is active at this point only slects the nodes that you are interested in (not other element or text nodes) then you can just do <xsl:when test="position()=last()"> otherwise you don't want position at all, you just want to know if there is (for example) no following-sibling download element which would be <xsl:when test="not(following-sibling::download)"> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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