Subject: Re: [xsl] select in the <xsl:param /> tag From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 3 Jul 2003 16:44:53 +0100 |
Hi Simon, > Am I right in saying that declaring the <xsl:param /> tag as follows > will make the named node set default to null if the template is > called without the <xsl:with-param /> tag. > > <xsl:param name="node-set" select=".." /> There's no such thing as "null" in XPath. The above <xsl:param> will make the $node-set parameter default to the parent of the context node at the point the template is called. Probably you meant: <xsl:param name="node-set" select="/.." /> which makes it default to an empty node set (since the root node, /, doesn't have a parent). > or is it > > <xsl:param name="node-set" select="" /> This is a syntax error: the select attribute contains an XPath expression and "" is not a legal XPath expression. Note that if you omit the select attribute (and don't have any content in <xsl:param>) then the default value for the parameter is an empty string. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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