Re: [xsl] select in the <xsl:param /> tag

["Simon Kelly" <kelly@xxxxxxxxxx>]

Thanks David, Jeni and Martinez,

Thanks for that. All set and correct now.

And am I right in thinking that if the select is "/.." then the test
not($node-set) will return true?

Cheers

Simon



----- Original Message -----
From: "Martinez, Brian" <brian.martinez@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, July 03, 2003 5:50 PM
Subject: RE: [xsl] select in the <xsl:param /> tag


> > From: Simon Kelly [mailto:kelly@xxxxxxxxxx]
> > Sent: Thursday, July 03, 2003 9:10 AM
> > Subject: [xsl] select in the <xsl:param /> tag
> >
> >
> > Am I right in saying that declaring the <xsl:param /> tag as
> > follows will
> > make the named node set default to null if the template is
> > called without
> > the <xsl:with-param /> tag.
> >
> > <xsl:param name="node-set" select=".." />
>
> This would create a node-set rooted at the parent of the context node, so
> it's not null.  In fact I don't believe this could ever be null, since all
> nodes except the root must have one parent.
>
> > or is it
> >
> > <xsl:param name="node-set" select="" />
>
> This isn't legal XSLT--the select attribute must be non-empty.
>
> cheers,
> b.
>
> | brian martinez                           brian.martinez@xxxxxxxxxxx |
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