RE: [xsl] select in the <xsl:param /> tag

[Américo Albuquerque <melinor@xxxxxxx>]

Hi

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Martinez, Brian
> Sent: Thursday, July 03, 2003 4:51 PM
> To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> Subject: RE: [xsl] select in the <xsl:param /> tag
> 
> 
> > From: Simon Kelly [mailto:kelly@xxxxxxxxxx]
> > Sent: Thursday, July 03, 2003 9:10 AM
> > Subject: [xsl] select in the <xsl:param /> tag
> > 
> > 
> > Am I right in saying that declaring the <xsl:param /> tag as
> > follows will
> > make the named node set default to null if the template is 
> > called without
> > the <xsl:with-param /> tag.
> > 
> > <xsl:param name="node-set" select=".." />
> 
> This would create a node-set rooted at the parent of the 
> context node, so it's not null.  In fact I don't believe this 
> could ever be null, since all nodes except the root must have 
> one parent.

It could be depending on where you define the parameter
Example:
<xsl:template match="/">
 <xsl:param name="nset" select=".."/>
 ...
</xsl:template>

Here nset will default to null, because the root node doesn't have a parent

If you define the parameter has a global one it probably be null as well,
although it might depend on the processor setting the root node has the
first one in the beginning or not




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