Re: [xsl] How to get output XML same as input XML?

[David Carlisle <davidc@xxxxxxxxx>]

If I read your samples correctly, what you are trying to say is that
your stylesheet copied an attribute interact:isParameter
to the result and did not place a suitable namespace declaration in the
linearisation of the result tree.

If so that does not show a limitation in XSLT, it is simply a bug in
your processor.



me>I suspect your terminology here is non standard. a well formed document
me>can only have one child element of the root node.

> Correct.  I am feeding two child elements of my root node separately to 
> separate callings of the XSL processor.
As I suspected, they are not children of the root node, they are
children of the topmost element, root nodes are not elements in Xpath.

> So the following will be picked up by the 
>processor as illegal:
>
><xsl:template name="openElement">
>  <myElement>
></xsl:template>

That of course isn't an XSLT restriction, the input would not be  passed
to XSLT at all as it wouldn't get past teh XML parser.


> If my output method is text then this problem does not happen.
that input would be an error to any XML application, and in particular
to XSLt, whatever output type.

>  Otherwise 
> I have to write more code which serializes every element into text, and I 
> would like to have as much of that done for me as I can.

It's only a couple of templates, or a single extension function, both of
which can easily be found in the archives, the work is already done for
you.

David

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