Subject: RE: [xsl] How to copy the previous operations? From: cknell@xxxxxxxxxx Date: Wed, 19 Nov 2003 12:50:14 -0500 |
You've got a misconception about the process of creating a new tree of nodes that is tipped by this statement " (which should have already copied the first group identifier a's signature part)". A stylesheet refers only to the input tree and itself. I does not have read access to the output tree. Therefor the notion that your stylesheet can refer to a tree fragment that has been "already copied" is fatally flawed. I think this problem can be resolved by recursive calls to a named template, but there isn't enough information to decide exactly how it should be structured. Is there a set number of <group> elements in a document, or is this arbitrary? -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: Ram <sram_30@xxxxxxxxx> Sent: Wed, 19 Nov 2003 08:21:57 -0800 (PST) To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] How to copy the previous operations? Hi, Can anyone help me out how to copy the previous operations? The xml source would look like this: <formatted-xml> <group><identifier>a</identifier> <signature>signature <identifier>DNSQuery1</identifier> <in>in<long>long</long><identifier>ant</identifier></in> </signature> </group> <group><identifier>b</identifier><identifier>a</identifier> <signature>signature<identifier>DNSQuery2</identifier> <inout>inout<string>string</string><identifier>grass</identifier></inout> </signature> </group> <group><identifier>c</identifier><identifier>b</identifier> <signature>signature<identifier>DNSQuery3</identifier> <out>out<boolean>boolean</boolean> <identifier>fish</identifier></out> </signature> </group> </formatted-xml> What I have to do is, I should copy the signature part the first group identifier 'a' to the signature part in group identifier 'b', because it is followed by the group identifier 'a'. Similarly, the third group identifier 'c' is followed by the second group identifier 'b' (which should have already copied the first group identifier a's signature part) and so the second group identifier's signature part should be copied to the third group identifier signature part. I tried the following xsl. <xsl:template match="group"> <xsl:if test="identifier[2]= preceding::group/identifier"> <xsl:copy> <xsl:apply-templates select="preceding::group/signature"/> </xsl:copy> </xsl:if> </xsl:template> But it didn't work. Thanks and regards, Ram __________________________________ Do you Yahoo!? Protect your identity with Yahoo! Mail AddressGuard http://antispam.yahoo.com/whatsnewfree XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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