RE: [xsl] How to copy the previous operations?

[Ram <sram_30@xxxxxxxxx>]

Charles,
 Actually, the input xml file is a dynamic one and the number of 'group'
is arbitrary. 
 "If a group identifier is followed by an identifier which was already
defined before, then the signature part of that group identifier should be
added to this signature part".
 I understand that I should use some recursive structure to fix this.
But, I don't know how.

What I tried was:

<xsl:template match="group">
	<xsl:variable name="groupID" select="identifier"/>
	group<xsl:text> </xsl:text><xsl:value-of  
                 select="$groupID"/>Interface {
	<xsl:call-template name="generation"/>	
	<xsl:apply-templates select="generation"/>
	<xsl:apply-templates select="group"/>
	}
</xsl:template>
<xsl:template name="generation" match="signature">
   <!--How the signature part output should look like goes here-->
   <!--Copying the previous group identifier signature part-->
   <xsl:if test="identifier[2]= preceding::group/identifier">
     <xsl:copy>
         <xsl:apply-templates select="preceding::group/signature"/>
      </xsl:copy>
   </xsl:if>
</xsl:template>

 But, couldn't get the desired output.
BR,
Ram





--- cknell@xxxxxxxxxx wrote:
> You've got a misconception about the process of creating a new tree of
> nodes that is tipped by this statement " (which should have already
> copied the first group identifier a's signature part)".
> 
> A stylesheet refers only to the input tree and itself. I does not have
> read access to the output tree. Therefor the notion that your stylesheet
> can refer to a tree fragment that has been "already copied" is fatally
> flawed.
> 
> I think this problem can be resolved by recursive calls to a named
> template, but there isn't enough information to decide exactly how it
> should be structured. Is there a set number of <group> elements in a
> document, or is this arbitrary?
> -- 
> Charles Knell
> cknell@xxxxxxxxxx - email
> 
> 
> 
> -----Original Message-----
> From:     Ram <sram_30@xxxxxxxxx>
> Sent:     Wed, 19 Nov 2003 08:21:57 -0800 (PST)
> To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  [xsl] How to copy the previous operations?
> 
> Hi,
>  Can anyone help me out how to copy the previous operations?
> The xml source would look like this:
> 
> <formatted-xml>
>   <group><identifier>a</identifier>
>    <signature>signature <identifier>DNSQuery1</identifier>
>      <in>in<long>long</long><identifier>ant</identifier></in>
>    </signature>
>   </group>
>   <group><identifier>b</identifier><identifier>a</identifier>
>     <signature>signature<identifier>DNSQuery2</identifier>              
>  
>        
>      
>
<inout>inout<string>string</string><identifier>grass</identifier></inout>
>     </signature>
>   </group>
>   <group><identifier>c</identifier><identifier>b</identifier>
>      <signature>signature<identifier>DNSQuery3</identifier>             
>  
>         
>        <out>out<boolean>boolean</boolean>
> <identifier>fish</identifier></out>
>      </signature>
>   </group>
> </formatted-xml>
> 
>     What I have to do is, I should copy the signature part the first
> group
> identifier 'a' to the signature part in group identifier 'b', because it
> is followed by the group identifier 'a'.
>     Similarly, the third group identifier 'c' is followed by the second
> group identifier 'b' (which should have already copied the 
> first group identifier a's signature part) and so the second group
> identifier's signature part should be copied to the third group
> identifier
> signature part.
> 
> I tried the following xsl.
> 
> <xsl:template match="group">
>   <xsl:if test="identifier[2]= preceding::group/identifier">
>      <xsl:copy>
>         <xsl:apply-templates select="preceding::group/signature"/>
>      </xsl:copy>
>   </xsl:if>
> </xsl:template>
>  
>   But it didn't work.
> 
> Thanks and regards,
> Ram
> 
> 
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