Subject: [xsl] GUI layout mechanism in XSLT From: Ilya Boyandin <ilyabo@xxxxxxxxx> Date: Wed, 5 Jan 2005 11:49:39 +0100 |
Hello All! I'm trying to implement a simple GUI layout mechanism with XSLT without much success for now. The problem is that the task requires to produce an output tree, which structure differs significantly from the original tree, and in which the elements are likely to be presented in a different order. Here's the problem description: The input is a GUI elements tree. Elements are contained in horizontal or vertical groups. Naturally, groups can contain other groups. For instance: <hgroup> <vgroup> <item>A1</item> <item>A2</item> </vgroup> <vgroup> <item>B1</item> <item>B2</item> <hgroup> <item>B3</item> <item>C3</item> </hgroup> </vgroup> </hgroup> The output must be one plain table (without nested tables!) in which the elements are layed out the same as in the input tree. So for the input tree above the output should be something like this: <table> <tr> <td>A1</td> <td colspan="2">B1</td> </tr> <tr> <td>A2</td> <td colspan="2">B2</td> </tr> <tr> <td> </td> <td>B3</td> <td>C3</td> </tr> </table> As I am a newbie, I don't see an obvious solution. I'd be very thankful if somebody could give me a hint or in the worst case make it clear that the problem cannot be solved with XSLT alone. Thank you! Ilya
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