Subject: Re: [xsl] including content files for output? From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> Date: Tue, 20 Dec 2005 18:50:30 +0100 |
Hi Eric, On 12/20/05, Eric Scheid <eric.scheid@xxxxxxxxxxxxxxx> wrote: > > I want to be able to include previously generated output files into the > output of the current xslt. For example, say an earlier process produced a > file "previous.html" containing this html snippet (and just this snippet): <xsl:copy-of select="document(<< Filename >>)/ol"/> If ol is the root element. But it has to be a valid XML document. I think you will need the xml declaration: <? xml version="1.0" ?> > On a hunch I tried both xsl:import and xsl:include but got the expected > error. Is there some way to do this? Those are constructs for including templates, not content. I hope this helps, Ragulf Pickaxe :-)
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