Subject: Re: [xsl] Sort before paging From: "Giancarlo Rossi" <giancarlo_rossi@xxxxxxxxxx> Date: Tue, 29 Aug 2006 15:19:23 +0200 |
The code have all the stylesheet tags. So it seems be a well format xml But it goes on error the same: I try with this one... But it doesn't works. <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:param name="start" select="1"/> <xsl:param name="range" select="5"/> <xsl:template match="/"> <xsl:call-template name="positionfilter"> <xsl:with-param name="sortedlist"> <xsl:for-each select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardL ist/Outward[position() >=$start and position() < $start + $range]" > <xsl:sort select="Price/Amount" data-type="number" order="ascending" /> <xsl:copy-of select="."/> </xsl:for-each> </xsl:with-param> </xsl:call-template/> </xsl:template> <xsl:template name="positionfilter"> <xsl:param name="sortedlist"/> <xsl:for-each select="$sortedlist/*[(position() >= $start) and (position() < $start + $range)]"> 'my code </xsl:for-each> </xsl:template> </xsl:stylesheet>
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