Subject: Re: [xsl] Testing implicit XHTML hierarchy From: "bryan rasmussen" <rasmussen.bryan@xxxxxxxxx> Date: Thu, 5 Jul 2007 02:13:51 +0200 |
sorry, have a pretty bad headache, and would like to avoid what I should be doing.
cheers, Bryan Rasmussen
well i agree there is redundancy (damn I should really do this stuff instead of messing around )
but
<xsl:variable name="h" select="//xhtml:*[matches(local-name(),'^h[1-6]')]/number(substring(local-name(),2))"/>
<xsl:for-each select="1 to count($h)-1"> <result select="$h[.+1][1]">
<xsl:value-of select="$h[.+1][1]"/> </result> <result select="$h[.][1]">
<xsl:value-of select="$h[.][1]"/> </result> <result select="$h[.+1][2]"> <xsl:value-of select="$h[.+1][2]"/> </result> <result select="$h[.][2]"><xsl:value-of select="$h[.][2]"/> </result> </xsl:for-each> </output> </xsl:template>
produces
<?xml version="1.0" encoding="UTF-8"?> <output> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> <result select="$h[.+1][1]">2</result> <result select="$h[.][1]">1</result> <result select="$h[.+1][2]">5</result> <result select="$h[.][2]">2</result> </output>
which I'm not following how $h[.+1][2] will always be empty?
Since there are two items in the sequence I mean. Sorry if I'm not very clear right now, but I am not thinking especially sharpish.
Cheers, Bryan Rasmussen
On 7/5/07, David Carlisle <davidc@xxxxxxxxx> wrote: > > > actually theres more than one item in your sequence that way. > I may have mistyped, but you shouldn't need the [1]'s in for example > $h[.+1][1] > as $h[.+1] is %h[position()=.+1] so can return at most 1 item, so [1] is > redundant. > similarly $h[.+1][2] will always be empty. > > David > > ________________________________________________________________________ > The Numerical Algorithms Group Ltd is a company registered in England > and Wales with company number 1249803. The registered office is: > Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. > > This e-mail has been scanned for all viruses by Star. The service is > powered by MessageLabs. > ________________________________________________________________________
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