Subject: [xsl] Select Deepest Node only in Iteration From: "J. Zhang" <j.zhang@xxxxxx> Date: Thu, 12 Jul 2007 16:47:15 +0200 |
I have already checked the XSL FAQ at http://www.dpawson.co.uk/ and explored the history of this mailinglist. I could not find the answer, that is why I am posting here. I am matching the content of XML elements this way in a for-each iteration: xsl:if test="matches(string(self::node()), concat('\W', $term, '\W'), 'im')"> I return the absolute path where $term occurs in the transformation. The result after the transformation is for example this for Word 1: //article //article/body[1] //article/body[1]/section[6] //article/body[1]/section[6]/normallist[6] //article/body[1]/section[6]/normallist[6]/item[1] The problem is that I only want the longest path, e.g. the deepest node of this leave. I need to set a condition that only returns something when the for-each iteration has come to the longest path of this leave, but I could not find a way to do this. Any help would be greatly appreciated! Thanks!
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[xsl] RE: xsl-list Digest 12 Jul 20, shi wudao | Thread | RE: [xsl] Select Deepest Node only , Michael Kay |
[xsl] RE: xsl-list Digest 12 Jul 20, shi wudao | Date | RE: [xsl] Select Deepest Node only , Michael Kay |
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