Re: [xsl] Finding the ID attribute of an XPath from XMLSchema

[mozer <xmlizer@xxxxxxxxx>]

On 7/21/07, v vijith <vvijith@xxxxxxxxx> wrote:
> Below is a snippet from the XMLSchema
>
> <xs:complexType name="nameType">
>                <xs:sequence>
>                        <xs:element minOccurs="0" ref="desig"/>
>                </xs:sequence>
>                <xs:attribute ref="dest" use="required"/>
>                <xs:attribute ref="id"/>
>                <xs:attribute ref="garageid"/>
>                <xs:attributeGroup ref="xlink:XLINKATT1"/>
>        </xs:complexType>
> <xs:attribute name="id" type="xs:ID"/>
>
> this means that in the XML, the nameType node can be identified by the
> id attribute as xs:attribute name=id is mapped to XS:ID.
>
> Likewise there can be many nodes in the XML that has ID associated to it.
>
> <xml>
> <root>
> <somenode>
> <nameType id="2" attrib2="34">text</nameType>
> <nameType id="3" attrib2="34">text</nameType>
> <nameType id="4" attrib2="34">text</nameType>
> </somenode>
> <anothernode attrib5="55"/>
> </root>

Just a sidenote

"2", "3" and "4" are not valid ID values...

Xmlizer