Re: [xsl] use of $foo/(//path)

[Florent Georges <lists@xxxxxxxxxxxx>]

Andrew Welch wrote:

  Hi Andrew,

> <xsl:sequence select="$actor/(//video[actorRef=$actor/@id])"/>

> What does the sequence constructor do for you here, as opposed to
> just:

> $actor//...

  The former selects all the video elements in the same document(s) as
$actor ($actor must be a sequence of node()*).  The later selects the
video elements that are descendant of $actor (so in the same
document(s) yes, but furthermore they need to have an ancestor
contained in $actor).

  Regards,

--drkm

























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