Re: [xsl] Count Ancestors Up To But Not Including a Given Type

[Eliot Kimber <ekimber@xxxxxxxxxxxx>]

David Carlisle wrote:

>     <xsl:sequence select="$n,$n/ancestor::*[node-name(.)=$lists][1][node-name(.)=node-name($n)]/f:same(.)"/>

It took my aging brain a bit to parse this out but I was able to adapt 
it to my code to get the correct answer. Here's how I understand this to 
work:

1. Construct a sequence consisting of the current node (which we know to 
be the starting list) and the results of steps 2-5:

2. Get the list of ancestors that are lists of any type: 
ancestor::*[node-name(.)=$lists]

3. Get the first (nearest) such ancestor: 
ancestor::*[node-name(.)=$lists][1]

4. For that nearest ancestor, see if its type is the same as the target 
type: [node-name(.)=node-name($n)]

5. If it is, apply f:same() to it: /f:same(.)

6. Return the result sequence

Cheers,

Eliot


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Eliot Kimber
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