Subject: Re: [xsl] Insert elment in XSD From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Thu, 28 Feb 2008 14:33:32 +0100 |
Now I have another problem. In the stylesheet article will be one param like this:
<xsl:param name="class">article</xsl:param>
Instead of use 'article' like in your solutions, I need to use $class
<xsl:template match="xs:element[@name=$class]/xs:complexType/xs:all">
but occurs an error and I don't know how correct it
Martin Honnen http://JavaScript.FAQTs.com/
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