Re: [xsl] xsl:copy- of and namespaces

["Alessandro Bologna" <alessandro.bologna@xxxxxxxxx>]

Off topic.
This list will never cease to amaze me. 3 valid answers, with
explanations, in 9 minutes. Kudos to all.
Alessandro



On Tue, Apr 1, 2008 at 11:19 AM, Florent Georges <lists@xxxxxxxxxxxx> wrote:
> Garvin Riensche wrote:
>
>  Hi
>
>
> > Can someone please tell me how I can give elements of a
> > subtree that are copied to the output with <xsl:copy-of
> > select="."> a new namespace?
>
>  The aim of xsl:copy-of is to, well, copy its arguments.
> If I understand you right (but that's not sure), you want to
> change the namespace URI part of the name of the elements to
> copy.  So that's not excatly a copy, but a transformation:
>
>    <xsl:template match="@*|node()">
>       <xsl:copy>
>          <xsl:apply-templates select="@*|node()"/>
>       </xsl:copy>
>    </xsl:template>
>
>    <xsl:template match="*" priority="0">
>       <xsl:element name="new:{ local-name(.) }">
>          <xsl:apply-templates select="@*|node()"/>
>       </xsl:element>
>    </xsl:template>
>
>  That means: copy everything, except the element nodes, in this case
> create a new element node whose the name is the same local-name but in
> the new namespace.
>
>  Regards,
>
> --drkm
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