Re: [xsl] most efficient way to get XML source's parent dir

On Feb 11, 2009, at 11:02 AM, Michael Kay wrote:

Well, I tried to simplify the example. In reality, I am using
the unparsed-text function which has no base-uri argument ()
and the resolver is provided with a full java.net.URI so I
needed a way to create the correct path in the XPath. I
should have been more clear.
Am I still missing something?
You should definitely be using functions like base-uri() and resolve- uri() rather than trying to manipulate the URI "by hand".

OK - Owen, thanks for questioning what I was doing. And thanks to both you and Mike for showing me the correct way to deal with it.

best,
-Rob

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Re: [xsl] How can one get the name of a template or function?, (continued) David Carlisle - 11 Feb 2009 16:37:34 -0000 Florent Georges - 11 Feb 2009 16:43:32 -0000 David Carlisle - 11 Feb 2009 16:50:15 -0000 Michael Kay - 11 Feb 2009 16:57:45 -0000 Robert Koberg - 11 Feb 2009 16:23:37 -0000 <=

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