[xsl] Simple newbie Q: literal as row title

["Dick Penny" <d_penny@xxxxxxx>]

As a newbie I have some XSLT working thanks to this group. I have moved to a
"named template" so that I can call template with different arguments - is
OK.
But I cannot figure out how to get a "fixed literal" as title of final
summary
row.

*************************fragment
    <!-- for each unique audit name -->
    <xsl:for-each  select="Row[@AuditName and
                generate-id(.)=generate-id(key('audits', @AuditName))]">
        <xsl:call-template name="one-row">
    	<xsl:with-param name="AuditN" select="@AuditName"/>
    	<xsl:with-param name="findings" select="key('audits', @AuditName)"/>
    	</xsl:call-template>
     </xsl:for-each>

     <!-- for all audits -->
     <xsl:call-template name="one-row">
         <xsl:with-param name="AuditN" select="TOTAL"/>
         <xsl:with-param name="findings" select="/dsQueryResponse/Rows/Row"/>
         </xsl:call-template>
*************************


Dick Penny