Subject: Re: [xsl] Re: adding column number to the entry From: ac <ac@xxxxxxxxxxxxx> Date: Thu, 03 Sep 2009 08:17:32 -0400 |
<xsl:template match="entry"> <cell Name="{substring(substring-after(., 'Table 1 TB C'), 1, 1)}" RowSpan="{if (xs:integer(@morerows)) then @morerows + 1 else 1}" ColumnSpan="1"> <xsl:value-of select="."/> </cell> </xsl:template>
Cheers, ac
Please help me on this issue.
Regards, Ganesh
On Tue, Sep 1, 2009 at 3:09 PM, Ganesh Babu N<nbabuganesh@xxxxxxxxx> wrote:
Dear All,
I am having a input like this.
<table> <row> <entry align="left" valign="top">Table 1 TB C1 R5</entry> <entry align="left" valign="top" morerows="1">Table 1 TB C2 R5 and TB C2 R6 are merged</entry> <entry align="left" valign="top">Table 1 TB C3 R5</entry> <entry align="left" valign="top">Table 1 TB C4 R5</entry> </row> <row> <entry align="left" valign="top">Table 1 TB C1 R6</entry> <entry align="left" valign="top">Table 1 TB C3 R6</entry> <entry align="left" valign="top">Table 1 TB C4 R6</entry> </row> </table>
My required output is as follows:
<table> <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R5</cell> <cell Name="2" RowSpan="2" ColumnSpan="1">Table 1 TB C2 R5 and TB C2 R6 are merged</cell> <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R5</cell> <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R5</cell> <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R6</cell> <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R6</cell> <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R6</cell> </table>
I have tried with the following code but it is changing the number in all the 2nd row entries. It requires to be changed only in C3 of R6 and C4 of R6. Because C2 of R6 is already merged with C2 of R5.
<xsl:template match="entry> <xsl:if test="parent::row/preceding-sibling::row/entry/@morerows"> <xsl:value-of select="position() + parent::row/preceding-sibling::row/entry[@morerows]/position()"/> </xsl:if> </xsl:template>
Please help me getting required output.
Regards, Ganesh
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