Subject: Re: [xsl] Re: adding column number to the entry From: Ganesh Babu N <nbabuganesh@xxxxxxxxx> Date: Fri, 4 Sep 2009 10:24:26 +0530 |
That is only sample text (Table 1 TB...). In the real life that is not possible. I need to provide the sequence number of entries in that row and give the number in the name attribute. name=1 for the first entry and name=2 to the second entry etc. When morerows=1 means when rowspan is there the entries in the next row should get incremented from the entry position in the previous row. look at the input and generate the output given. Thanks are regards, Ganesh On Thu, Sep 3, 2009 at 5:47 PM, ac<ac@xxxxxxxxxxxxx> wrote: > Hi, > > I may be missing something, but how about something along the lines of: > > <xsl:template match="entry"> > <cell Name="{substring(substring-after(., 'Table 1 TB C'), 1, > 1)}" RowSpan="{if (xs:integer(@morerows)) then @morerows + 1 else 1}" > ColumnSpan="1"> > <xsl:value-of select="."/> > </cell> > </xsl:template> > > Cheers, > ac > > > >> Please help me on this issue. >> >> Regards, >> Ganesh >> >> >> On Tue, Sep 1, 2009 at 3:09 PM, Ganesh Babu N<nbabuganesh@xxxxxxxxx> >> wrote: >> >>> >>> Dear All, >>> >>> I am having a input like this. >>> >>> <table> >>> <row> >>> <entry align="left" valign="top">Table 1 TB C1 R5</entry> >>> <entry align="left" valign="top" morerows="1">Table 1 TB C2 >>> R5 and >>> TB C2 R6 are merged</entry> >>> <entry align="left" valign="top">Table 1 TB C3 R5</entry> >>> <entry align="left" valign="top">Table 1 TB C4 R5</entry> >>> </row> >>> <row> >>> <entry align="left" valign="top">Table 1 TB C1 R6</entry> >>> <entry align="left" valign="top">Table 1 TB C3 R6</entry> >>> <entry align="left" valign="top">Table 1 TB C4 R6</entry> >>> </row> >>> </table> >>> >>> My required output is as follows: >>> >>> <table> >>> <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R5</cell> >>> <cell Name="2" RowSpan="2" ColumnSpan="1">Table 1 TB C2 R5 and TB >>> C2 R6 are merged</cell> >>> <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R5</cell> >>> <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R5</cell> >>> <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R6</cell> >>> <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R6</cell> >>> <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R6</cell> >>> </table> >>> >>> I have tried with the following code but it is changing the number in >>> all the 2nd row entries. It requires to be changed only in C3 of R6 >>> and C4 of R6. Because C2 of R6 is already merged with C2 of R5. >>> >>> <xsl:template match="entry> >>> <xsl:if test="parent::row/preceding-sibling::row/entry/@morerows"> >>> <xsl:value-of select="position() + >>> parent::row/preceding-sibling::row/entry[@morerows]/position()"/> >>> </xsl:if> >>> </xsl:template> >>> >>> Please help me getting required output. >>> >>> Regards, >>> Ganesh
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