Subject: Re: [xsl] Re: adding column number to the entry From: ac <ac@xxxxxxxxxxxxx> Date: Fri, 04 Sep 2009 09:52:22 -0400 |
The template provided does exactly transform the input provided to the sample output provided.
The fact that you are introducing new constraints only shows that your problem is not clearly expressed.
There may be other ways to track the index from the content and the relationship between the entries could also be different.
As everything could change, it is difficult for me to justify the time to address all possibilities.
1. provide the smallest possible example that illustrates your question. (it looks to me like there is a lot of "clutter" in your example; for example cell names and columnspans are not needed to deal with the question you asked)
2. in addition to a small example describe in words, where the information in the desired result would come from in the input. Is it the case that you want RowSpan to equal 1 unless the value of the cell element is longer than 16 characters? Or is there some other logic that you want implemented in your XSLT?
Note that expressing the problem clearly may itself provide you with a solution path.
Cheers, ac
That is only sample text (Table 1 TB...). In the real life that is not possible.
I need to provide the sequence number of entries in that row and give the number in the name attribute. name=1 for the first entry and name=2 to the second entry etc. When morerows=1 means when rowspan is there the entries in the next row should get incremented from the entry position in the previous row.
look at the input and generate the output given.
Thanks are regards, Ganesh
On Thu, Sep 3, 2009 at 5:47 PM, ac<ac@xxxxxxxxxxxxx> wrote:
Hi,
I may be missing something, but how about something along the lines of:
<xsl:template match="entry"> <cell Name="{substring(substring-after(., 'Table 1 TB C'), 1, 1)}" RowSpan="{if (xs:integer(@morerows)) then @morerows + 1 else 1}" ColumnSpan="1"> <xsl:value-of select="."/> </cell> </xsl:template>
Cheers, ac
Please help me on this issue.
Regards, Ganesh
On Tue, Sep 1, 2009 at 3:09 PM, Ganesh Babu N<nbabuganesh@xxxxxxxxx> wrote:
Dear All,
I am having a input like this.
<table> <row> <entry align="left" valign="top">Table 1 TB C1 R5</entry> <entry align="left" valign="top" morerows="1">Table 1 TB C2 R5 and TB C2 R6 are merged</entry> <entry align="left" valign="top">Table 1 TB C3 R5</entry> <entry align="left" valign="top">Table 1 TB C4 R5</entry> </row> <row> <entry align="left" valign="top">Table 1 TB C1 R6</entry> <entry align="left" valign="top">Table 1 TB C3 R6</entry> <entry align="left" valign="top">Table 1 TB C4 R6</entry> </row> </table>
My required output is as follows:
<table> <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R5</cell> <cell Name="2" RowSpan="2" ColumnSpan="1">Table 1 TB C2 R5 and TB C2 R6 are merged</cell> <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R5</cell> <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R5</cell> <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R6</cell> <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R6</cell> <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R6</cell> </table>
I have tried with the following code but it is changing the number in all the 2nd row entries. It requires to be changed only in C3 of R6 and C4 of R6. Because C2 of R6 is already merged with C2 of R5.
<xsl:template match="entry> <xsl:if test="parent::row/preceding-sibling::row/entry/@morerows"> <xsl:value-of select="position() + parent::row/preceding-sibling::row/entry[@morerows]/position()"/> </xsl:if> </xsl:template>
Please help me getting required output.
Regards, Ganesh
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