Re: [xsl] sorting into a tree structure

[jim mcgovern <jim.mcgovern2@xxxxxxxxxxxxxx>]

Just one more point if I may....?

I'd like to limit the number of levels that the tree goes down.
What's the best way of achieving this?  Is this through
count(ancestor::*)?

On Tue, Oct 6, 2009 at 5:13 PM, jim mcgovern
<jim.mcgovern2@xxxxxxxxxxxxxx> wrote:
> And I'm sorry for being so daft for missing it!
>
> Of course that works.  Many thanks!
>
> On Tue, Oct 6, 2009 at 5:09 PM, Martin Honnen <Martin.Honnen@xxxxxx> wrote:
>> jim mcgovern wrote:
>>
>>> I've tried your suggestion but it didn't seem to affect the order
>>> unfortunately. :(
>>
>> Sorry, I forgot the '@' in front of 'order' in the select attribute so use
>>
>>    <xsl:template match="Item">
>>        <xsl:choose>
>>            <xsl:when test="key('val', @ID)">
>>                <li><xsl:value-of select="@title"/></li>
>>                <ul>
>>                  <xsl:apply-templates select="key('val', @ID)">
>>                    <xsl:sort select="@order" data-type="number"/>
>>                  </xsl:apply-templates>
>>                </ul>
>>            </xsl:when>
>>            <xsl:otherwise>
>>                <li><xsl:value-of select="@title"/></li>
>>            </xsl:otherwise>
>>        </xsl:choose>
>>    </xsl:template>
>>
>>
>> --
>>
>>        Martin Honnen
>>        http://msmvps.com/blogs/martin_honnen/