Subject: Re: [xsl] sorting into a tree structure From: jim mcgovern <jim.mcgovern2@xxxxxxxxxxxxxx> Date: Tue, 6 Oct 2009 17:40:43 +0100 |
Just one more point if I may....? I'd like to limit the number of levels that the tree goes down. What's the best way of achieving this? Is this through count(ancestor::*)? On Tue, Oct 6, 2009 at 5:13 PM, jim mcgovern <jim.mcgovern2@xxxxxxxxxxxxxx> wrote: > And I'm sorry for being so daft for missing it! > > Of course that works. Many thanks! > > On Tue, Oct 6, 2009 at 5:09 PM, Martin Honnen <Martin.Honnen@xxxxxx> wrote: >> jim mcgovern wrote: >> >>> I've tried your suggestion but it didn't seem to affect the order >>> unfortunately. :( >> >> Sorry, I forgot the '@' in front of 'order' in the select attribute so use >> >> <xsl:template match="Item"> >> <xsl:choose> >> <xsl:when test="key('val', @ID)"> >> <li><xsl:value-of select="@title"/></li> >> <ul> >> <xsl:apply-templates select="key('val', @ID)"> >> <xsl:sort select="@order" data-type="number"/> >> </xsl:apply-templates> >> </ul> >> </xsl:when> >> <xsl:otherwise> >> <li><xsl:value-of select="@title"/></li> >> </xsl:otherwise> >> </xsl:choose> >> </xsl:template> >> >> >> -- >> >> Martin Honnen >> http://msmvps.com/blogs/martin_honnen/
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