Re: [xsl] sorting into a tree structure

[Martin Honnen <Martin.Honnen@xxxxxx>]

jim mcgovern wrote:

> I'd like to limit the number of levels that the tree goes down.
> What's the best way of achieving this?  Is this through
> count(ancestor::*)?

Your input is a flat list so using the ancestor axis on the input does 
not help.
Are you thinking about using the ancestor axis on the output tree? With 
XSLT 1.0 you can't use XPath on result tree or temorary trees without 
using an extension function like exsl:node-set.

But you could pass a level down your template e.g.

    <xsl:template match="folders">
        <ul>
          <xsl:apply-templates select="key('val', '')">
            <xsl:with-param name="level" select="1"/>
          </xsl:apply-templates>
        </ul>
    </xsl:template>

    <xsl:template match="Item">
        <xsl:param name="level"/>
        <xsl:choose>
            <xsl:when test="key('val', @ID) and $level &lt;= $max-level">
                <li><xsl:value-of select="@title"/></li>
                <ul>
                  <xsl:apply-templates select="key('val', @ID)">
                    <xsl:sort select="@order" data-type="number"/>
                    <xsl:with-param name="level" select="$level + 1"/>
                  </xsl:apply-templates>
                </ul>
            </xsl:when>
            <xsl:otherwise>
                <li><xsl:value-of select="@title"/></li>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>

  <xsl:param name="max-level" select="10"/>

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/