Subject: Re: [xsl] sorting into a tree structure From: Manfred Staudinger <manfred.staudinger@xxxxxxxxx> Date: Tue, 6 Oct 2009 18:52:53 +0200 |
Hi jim, You should be aware that for example <ul> <li>item1</li> <ul> <li>item6</li> </ul> </ul> is invalid in terms of html (ul can not be a child of ul). A valid version would be: <ul> <li>item1 <ul> <li>item6</li> </ul> </li> </ul> Regards, Manfred On 06/10/2009, jim mcgovern <jim.mcgovern2@xxxxxxxxxxxxxx> wrote: > Just one more point if I may....? > > I'd like to limit the number of levels that the tree goes down. > What's the best way of achieving this? Is this through > count(ancestor::*)? > > On Tue, Oct 6, 2009 at 5:13 PM, jim mcgovern > <jim.mcgovern2@xxxxxxxxxxxxxx> wrote: >> And I'm sorry for being so daft for missing it! >> >> Of course that works. Many thanks! >> >> On Tue, Oct 6, 2009 at 5:09 PM, Martin Honnen <Martin.Honnen@xxxxxx> >> wrote: >>> jim mcgovern wrote: >>> >>>> I've tried your suggestion but it didn't seem to affect the order >>>> unfortunately. :( >>> >>> Sorry, I forgot the '@' in front of 'order' in the select attribute so >>> use >>> >>> <xsl:template match="Item"> >>> <xsl:choose> >>> <xsl:when test="key('val', @ID)"> >>> <li><xsl:value-of select="@title"/></li> >>> <ul> >>> <xsl:apply-templates select="key('val', @ID)"> >>> <xsl:sort select="@order" data-type="number"/> >>> </xsl:apply-templates> >>> </ul> >>> </xsl:when> >>> <xsl:otherwise> >>> <li><xsl:value-of select="@title"/></li> >>> </xsl:otherwise> >>> </xsl:choose> >>> </xsl:template> >>> >>> >>> -- >>> >>> Martin Honnen >>> http://msmvps.com/blogs/martin_honnen/
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