Re: [xsl] set union? xslt 2.0

[Martin Honnen <Martin.Honnen@xxxxxx>]

Dave Pawson wrote:

> <xsl:template 
>   match="skillarea[tokenize(@targets,'|')=tokenize($param,'|')]"/>
>
> This is the 'odd' meaning of = in xslt 2?
> If any item on LHS is present in RHS then = returns true.

It is not much different to '=' in XSLT/XPath 1.0 only instead of 
comparing node-sets it has been generalized to comparing sequences of 
items. But already with XPath 1.0 if you compare to node-sets e.g.
  $foo = $bar
then the comparison is true if there is at least one node in $foo and in 
$bar for which the comparison is true.

> Issue:
>   What happens with tokenize when the separator is missing?
> empty set? 

No, the first argument string is returned.

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/