Re: [xsl] URI's, double backslashes and regular expressions

[Michael Kay <mike@xxxxxxxxxxxx>]

On 28/10/2010 19:51, Neil Owens wrote:
> I just can't figure out the syntax here
>
> I'm passing a directory location into Saxon as a parameter.  Only I need to make every '\' character in the (windows) directory path a '\\' for the uri in the transform.  As it's only the transform that needs this I thought I'd do the conversion in the transform.  And it's beaten me.

The href attribute of xsl:result-document expects a URI, not a Windows 
filename, and URIs always use forward slashes to separate components of 
the path.

Even if it were a backslash, the backslash is not a special character in 
XPath and does not need escaping.

Moreover: string concatenation is an unreliable way of constructing a 
URI from a base URI plus a relative reference. Much better to use the 
resolve-uri() function. (I'm afraid this is advice I don't always follow 
myself, but I often end up regretting it.)

Michael Kay
Saxonica
> The command line param is: ...path="C:\Documents and Settings\Adminis
> trator\My Documents\Projects\Transform\OutputFiles"
>
> I've got this neatly passed into the transform with:
>
> <xsl:param name="path"></xsl:param>
> ...
> <xsl:template match="Log">
>          <xsl:value-of select= replace($path, '\\', '\\')" />
>          <xsl:variable name="Command" select="concat($path, '\\OutputFiles\\Command-output.xml')" />
>          <xsl:result-document method="xml" href="{$Command}">
>          .....
>
>
> But fails and I just can't figure out how to achieve setting the result-document href to equal "C:\\Documents and Settings\\Administrator\\My Documents\\Projects\\Transform\OutputFiles"
>
> I know I can (I tried and it works) just add the correct number of backslashes to the command line param, but I don't want to.
>
> As ever, thanks in advance...