RE: [xsl] Issue with Xalan nodeset

Subject: RE: [xsl] Issue with Xalan nodeset
From: "Etheridge, Stephen" <stephen.etheridge@xxxxxxxxxx>
Date: Fri, 26 Nov 2010 08:23:48 +0000
Martin

Making the change suggested makes no difference to the output apart from
the inclusion of the standard XML PI - <?xml   etc.)


Kind regards
Stephen

-----Original Message-----
From: Martin Honnen [mailto:Martin.Honnen@xxxxxx]
Sent: 25 November 2010 16:49
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Issue with Xalan nodeset

Etheridge, Stephen wrote:

> <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:xalan="http://xml.apache.org/xalan";
> exclude-result-prefixes = "xalan">
>
> <xsl:output method="text" indent="yes" />
> <xsl:variable name="old_file" select="/*"></xsl:variable>
> <xsl:param name="secondFile"></xsl:param>
> <xsl:variable name="new_file"
select="xalan:nodeset($secondFile)/*"></xsl:variable>
>
> 	<xsl:template match="/">
> 		Parameter secondFile is set as
> 		<xsl:value-of select="$secondFile"/>

What does output method="xml" and
                 <xsl:copy-of select="$secondFile"/>
give you for your input?
I am not familiar with the types Xalan allows as parameters and how Java

types are mapped to XSLT/XPath types.
Are you using Xalan XSLTC or Interpreter? Have you tried to set the
parameter to an XSLTCSource
http://xml.apache.org/xalan-j/xsltc/xsltc_trax_api.html instead of a
DOMSource?

--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/



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