RE: [xsl] XSLT transformation using counters

[Bubba O'Reily <killswi7ch1@xxxxxxxx>]

Now I'm confused. Maybe XML output is not the way to go? SHould it be just
"text"? Bascially I have a well-formed XML file as input. I need to translate
all the elements to tags using the syntax below (ex. <ParaStyle:SOME_NAME>)

Any <a href="??">...<a/>, <i>...</i> would also require replacing. So I will
need to replace </ elements to.

What is the best method to perform this task?




> Date: Wed, 27 Apr 2011 13:17:37 +0100
> From: davidc@xxxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> CC: killswi7ch1@xxxxxxxx
> Subject: Re: [xsl] XSLT transformation using counters
>
> On 27/04/2011 12:40, Bubba O'Reily wrote:
> >
> >
> > I want to export XML.
>
> then it would really help people understand your requirements if the
> required output that you showed was well formed xml, so far (including
> this last mail) that has never been the case. Where do you want your
> elements to close?
>
>
> > There are other elements I also neeed to replace in the file.
> > If I output method="text" then those disappear in the output. For
> example<a href="??">...</a>
>
>
> text output doesn't contain elements, but (the reason I mentioned it) is
> that if you are generating text then the string <foo> will be output as
> that, not as &lt;foo&gt; so there is no need for disable-output-escaping
> (as no escaping happens for plain text). However, if you are generating
> xml this is not relevant.
>
>
> > I'm getting alot closer but how do I decrement the counter when a
> > heading appears outside of a</lev>. See example input, output& code
> > below. Note the output on the following lines:
> >
>
> XSLT doesn't have counters, If you specify what needs to be counted with
> the attributes to xsl:number then the correct number should be output.
>
> > <ParaStyle:hd4>Level 3
> > <ParaStyle:para>para text
> > <ParaStyle:hd4>Level 2
> > <ParaStyle:para>para text
> > <ParaStyle:hd4>Level 1
> > <ParaStyle:para>para text
> >
> > The<ParaStyle:hd?> is not correct. I need to decrement the counter
> > so
> when a</lev> occurs the appropriate counter is used.
> >
> > Should be:
> >
> > <ParaStyle:hd3>Level 3
> > <ParaStyle:para>para text
> > <ParaStyle:hd2>Level 2
> > <ParaStyle:para>para text
> > <ParaStyle:hd1>Level 1
> > <ParaStyle:para>para text
> >
> >
> >
> >
> > Input:
> > ------
> >
> > <lev>
> > <heading>Level 1</heading>
> > <para>para text</para>
> > <heading>Level 1A</heading>
> > <para>para text</para>
> > <lev>
> > <heading>Level 2</heading>
> > <para>para text</para>
> > <heading>Level 2A</heading>
> > <para>para text</para>
> > <heading>Level 2B</heading>
> > <para>para text</para>
> > <lev>
> > <heading>Level 3</heading>
> > <para>para text</para>
> > <lev>
> > <heading>Level 4</heading>
> > <para>para text</para>
> > <heading>Level 4A</heading>
> > <para>para text</para>
> > <heading>Level 4B</heading>
> > <para>para text</para>
> > </lev>
> > <heading>Level 3</heading>
> > <para>para text</para>
> > </lev>
> > <heading>Level 2</heading>
> > <para>para text</para>
> > </lev>
> > <heading>Level 1</heading>
> > <para>para text</para>
> > </lev>
> >
> >
> >
> >
> > Output Required:
> > ----------------
>
> This output is not well formed and so will generate a fatal error in any
> XML tool. It is virtually impossible to generate non well formed XML in
> XSLT unless you use disable-output escaping.
>
> If you showed a well formed example of your required output, then
> someone could show you how to generate it.
>
> >
> >
> > <ParaStyle:lev>
> > <ParaStyle:hd1>Level 1
> > <ParaStyle:para>para text
> > <ParaStyle:hd1>Level 1A
> > <ParaStyle:para>para text
>
>
> David
>
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