Subject: Re: [xsl] XSLT transformation using counters From: Jeff Sese <jeferson.sese@xxxxxxxxxxxx> Date: Thu, 28 Apr 2011 16:16:09 +0800 |
Now I'm confused. Maybe XML output is not the way to go? SHould it be just "text"? Bascially I have a well-formed XML file as input. I need to translate all the elements to tags using the syntax below (ex. <ParaStyle:SOME_NAME>)
Any <a href="??">...<a/>, <i>...</i> would also require replacing. So I will need to replace </ elements to.
What is the best method to perform this task?
Date: Wed, 27 Apr 2011 13:17:37 +0100 From: davidc@xxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx CC: killswi7ch1@xxxxxxxx Subject: Re: [xsl] XSLT transformation using counters
On 27/04/2011 12:40, Bubba O'Reily wrote:
I want to export XML.
then it would really help people understand your requirements if the
required output that you showed was well formed xml, so far (including
this last mail) that has never been the case. Where do you want your
elements to close?
example<a href="??">...</a>There are other elements I also neeed to replace in the file. If I output method="text" then those disappear in the output. For
text output doesn't contain elements, but (the reason I mentioned it) is
that if you are generating text then the string <foo> will be output as
that, not as <foo> so there is no need for disable-output- escaping
(as no escaping happens for plain text). However, if you are generating
xml this is not relevant.
I'm getting alot closer but how do I decrement the counter when a heading appears outside of a</lev>. See example input, output& code below. Note the output on the following lines:
XSLT doesn't have counters, If you specify what needs to be counted with
the attributes to xsl:number then the correct number should be output.
when a</lev> occurs the appropriate counter is used.<ParaStyle:hd4>Level 3 <ParaStyle:para>para text <ParaStyle:hd4>Level 2 <ParaStyle:para>para text <ParaStyle:hd4>Level 1 <ParaStyle:para>para text
The<ParaStyle:hd?> is not correct. I need to decrement the counter so
Should be:
<ParaStyle:hd3>Level 3 <ParaStyle:para>para text <ParaStyle:hd2>Level 2 <ParaStyle:para>para text <ParaStyle:hd1>Level 1 <ParaStyle:para>para text
Input: ------
<lev> <heading>Level 1</heading> <para>para text</para> <heading>Level 1A</heading> <para>para text</para> <lev> <heading>Level 2</heading> <para>para text</para> <heading>Level 2A</heading> <para>para text</para> <heading>Level 2B</heading> <para>para text</para> <lev> <heading>Level 3</heading> <para>para text</para> <lev> <heading>Level 4</heading> <para>para text</para> <heading>Level 4A</heading> <para>para text</para> <heading>Level 4B</heading> <para>para text</para> </lev> <heading>Level 3</heading> <para>para text</para> </lev> <heading>Level 2</heading> <para>para text</para> </lev> <heading>Level 1</heading> <para>para text</para> </lev>
Output Required: ----------------
This output is not well formed and so will generate a fatal error in any
XML tool. It is virtually impossible to generate non well formed XML in
XSLT unless you use disable-output escaping.
If you showed a well formed example of your required output, then someone could show you how to generate it.
<ParaStyle:lev> <ParaStyle:hd1>Level 1 <ParaStyle:para>para text <ParaStyle:hd1>Level 1A <ParaStyle:para>para text
David
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