[xsl] __LINE__ equivalent in XSTL

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[xsl] LINE equivalent in XSTL

Subject: [xsl] __LINE__ equivalent in XSTL
From: Bartolomeo Nicolotti <bnicolotti@xxxxxxxxx>
Date: Fri, 02 Dec 2011 13:14:57 +0100

To whom it may concern,

in C there's a pre-processor directive

__LINE__

that gives you the line of source where the directive is.

Is there an equivalent in XSLT?

Many thanks

Best regards

Bartolomeo

Current Thread
[xsl] __LINE__ equivalent in XSTL Bartolomeo Nicolotti - 2 Dec 2011 12:15:10 -0000 <= G. Ken Holman - 2 Dec 2011 12:24:20 -0000 Bartolomeo Nicolotti - 2 Dec 2011 12:43:21 -0000 Bartolomeo Nicolotti - 2 Dec 2011 12:44:29 -0000 Andrew Welch - 2 Dec 2011 12:55:53 -0000

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