Re: [xsl] Assigning new attribute value

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 20.12.2016 21:11, Mark Wilson pubs@xxxxxxxxxxxx wrote:
> I am doing an identity transformation that has presented me with a
> problem. The element <Location> in the original XML must have one and
> only one of seven possible attributes. Whichever attribute is present, I
> must keep its name but change its value. I have created a brute-force
> template that I assume will work. It ascertains the attribute's name and
> assigns it a new value. This is so ugly I am hanging my head in shame.
> There must be a more elegant method
> Mark
>
> xsl:template match="Location">
>      <xsl:param name="placement-index"/>
>          <Location>
>            <xsl:choose>
>                <xsl:when test="@minisheet">
>                    <xsl:attribute name="minisheet"
> select="$placement-index"/>
>                </xsl:when>
>                <xsl:when test="@souvenir-sheet">
>                    <xsl:attribute name="souvenir-sheet"
> select="$placement-index"/>
>                </xsl:when>
>                <xsl:when test="@gutter">
>                    <xsl:attribute name="gutter" select="$placement-index"/>
>                </xsl:when>
>            </xsl:choose>
>
> <!-- There are more attribute names, but you get the idea -->
>
>          </Location>
>   </xsl:template>

So any attribute present gets that new, same value? Then simply do

  <xsl:template match="Location/@*">
    <xsl:param name="placement-index"/>
    <xsl:attribute name="{name()}" select="$placement-index"/>
  </xsl:template>


and have

  <xsl:template match="Location">
     <xsl:param name="placement-index"/>
     <xsl:copy>
        <xsl:apply-templates select="@*">
          <xsl:with-param name="placement-index" 
select="$placement-index"/>
        </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>