Re: [xsl] compare two node sets

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 19.01.2020 22:21, Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx
wrote:
> Thank you, David, Michael, and Liam for the prompt replies! Michael's
> solution seems to be the simplest to implement. I use Saxon 9 HE, so
> XPath 2.0 should be okay. And, indeed, quadratic performance should not
> be an issue. However, Saxon throws the following error:
>
> XPST0003: Unexpected token "every" at start of expression
>
> Is there a typo in the expression? I used the expression as given:
>
> <xsl:when test="count(//director) eq count(//author) and every $d in
> //director satisfies some $a in //author satisfies deep-equal($d/*, $a/*)">
>
> To clarify, the context node is the <film> element.

I think you need to put the `every` expression into parenthesis, and in
the context of a `film` element it suffices to use child selection, so
to simplify:

count(director) eq count(author) and (every $d in director satisfies
some $a in author satisfies deep-equal($d/*, $a/*))