Re: [xsl] compare two node sets

Subject: Re: [xsl] compare two node sets
From: "Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Sun, 19 Jan 2020 21:36:12 -0000
I think you need to put the `every` expression into parenthesis, and in
the context of a `film` element it suffices to use child selection, so
to simplify:

count(director) eq count(author) and (every $d in director satisfies
some $a in author satisfies deep-equal($d/*, $a/*))

Yes, like that it works. Thank you!


Wolfhart

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