Re: [xsl] compare two node sets

Subject: Re: [xsl] compare two node sets
From: "Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 21 Jan 2020 16:34:09 -0000
Hi Wendell,

Thank you for your solution. I have a question about it, which has to do with the fact that, in my case, the <author>/<director> elements also may have a <middle> child element, which I did not mention in my original post. Now, if I understand correctly, your solution does not differentiate between

B B B B B B B  <director>
B B B B B B B B B B  <first>J.</first>
B B B B B B B B B B  <middle>R.</first>
B B B B B B B B B B  <last>Doe</last>
B B B B B B B  </director>

and

B B B B B B B  <director>
B B B B B B B B B B  <first>J. R.</first>
B B B B B B B B B B  <last>Doe</last>
B B B B B B B  </director>

Is that right? (I am not saying that this is necessarily a problem. It may even be seen as a feature rather than a bug. I just want to be sure that I understand the solution correctly.)

Best,
Wolfhart


On 21.01.20 12:42, Piez, Wendell A. (Fed) wendell.piez@xxxxxxxx wrote:
Hi,

Another solution not yet suggested in this thread is to avoid deep-equal() and rely on a signature function.

So for example,

<xsl:function name="f:signature" as="xs:string">
   <xsl:param name="who" as="node()"/>
   <xsl:value-of select="string-join($who/(first, last), ' ')"/>
</xsl:function>


Then your list of author-directors is //author[f:signature(.)=parent::film/child::director/f:signature(.)]


(Or the other way around.)

Wrap the expression in the filter in not() to retrieve authors who did not direct, etc.

One advantage of this approach is it's easy to adjust the signature logic to real-world exigencies.

Cheers, Wendell

-----Original Message-----
From: Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Sunday, January 19, 2020 4:22 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] compare two node sets

Thank you, David, Michael, and Liam for the prompt replies! Michael's solution seems to be the simplest to implement. I use Saxon 9 HE, so XPath 2.0 should be okay. And, indeed, quadratic performance should not be an issue. However, Saxon throws the following error:

XPST0003: Unexpected token "every" at start of expression

Is there a typo in the expression? I used the expression as given:

<xsl:when test="count(//director) eq count(//author) and every $d in //director satisfies some $a in //author satisfies deep-equal($d/*, $a/*)">

To clarify, the context node is the <film> element.

Wolfhart


On 19.01.20 17:55, Liam R. E. Quin liam@xxxxxxxxxxxxxxxx wrote:
On Sun, 2020-01-19 at 20:37 +0000, Wolfhart Totschnig
wolfhart.totschnig@xxxxxxxxxxx wrote:
Hello,

I have an XSL/XPath problem to which I cannot find the solution. I
have an xml file with data about films, in the following form
(simplified):

[..]
. By contrast, in the following example the test should return
<false>:

      <film>
         <title>M</title>
         <director>
            <first>Fritz</first>
            <last>Lang</last>
         </director>
         <author>
            <first>Thea von</first>
            <last>Harbou</last>
         </author>
         <author>
            <first>Fritz</first>
            <last>Lang</last>
         </author>
      </film>
Why?

As stated,
   <xsl:mode on-no-match="shallow-copy" />

    <xsl:template match="/">
      <xsl:apply-templates select="/films/film[
          some $a in author satisfies
          (
              ($a/first = director/first)
              and ($a/last = director/last)
          )
      ]"/>
    </xsl:template>

Liam

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