Re: [xsl] compare two node sets

Subject: Re: [xsl] compare two node sets
From: "Piez, Wendell A. (Fed) wendell.piez@xxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 21 Jan 2020 17:23:49 -0000
Liam: Yes. It is the definition of "the same" that is at the heart of this
problem (as of so many).

Cheers, Wendell

-----Original Message-----
From: Liam R. E. Quin liam@xxxxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, January 21, 2020 11:42 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] compare two node sets

On Tue, 2020-01-21 at 15:42 +0000, Piez, Wendell A. (Fed)
wendell.piez@xxxxxxxx wrote:
> Hi,
>
> Another solution not yet suggested in this thread is to avoid deep-
> equal() and rely on a signature function.
Yes. I admit i tend to avoid deep-equal for this sort of thing because of its
behaviour with comments or processing instructions, and because the definition
of equality tends to vary over time - e.g. wanting to ignore prefix and
suffic/credentials elements or needing a case- insensitive comparison on
family name to cope with latin transcriptions of Japanese family names.

But that depends on the business context - the source of the data and who
mantains the various parts of the XSLT.

Liam

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