Re: [xsl] replace a string that is in between two specific chars in XSLT 1.0

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Am 13.10.2021 um 17:31 schrieb Prady Prady prady.chin@xxxxxxxxx:
> Team,
>
>
> Can somebody help me to replace string that is in between*# and ;*
> with blank. I need to include this is oracle bpel which only supports
> xslt 1.0
>
> From:
> <IpsCollection xmlns="http://xmlns.oracle.com/aa
> <http://xmlns.oracle.com/aa>">
> <Ips>
> *<Ip>q1#11.11.11.111;q2#22.22.22.22</Ip>*

Were is the second semicolon ";" after the second "#" so that the string
"in between" can be found and removed?


> </Ips>
> B </IpsCollection>
> To:
> *B <v2:Ops xmlns:v2="http://xmlns.ieee.org/V2 <http://xmlns.ieee.org/V2>">*
> <v2:nums>q1;q2</v2:nums>
> B </v2:Ops>
>
>
> Thank you veryB much for your help!
>
>
> XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list>
> EasyUnsubscribe <http://lists.mulberrytech.com/unsub/xsl-list/582271>
> (by email <>)