Re: [xsl] replace a string that is in between two specific chars in XSLT 1.0

["Prady Prady prady.chin@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Thank you very much for your reply, David.

As you guessed, input string can have any number of ; and # => any
number of ; and # and you want to delete any text between adjacent #
and ; (as the title of the thread implies

To further clarify:  aaa#bbbb;ccc#dd;
1. ';' marks the end of each set : eg: set 1 :  aaa#bbbb  Set 2 : ccc#dd;
2. Each set has '#' as the demarcation : for eg:  token 1 : aaa and token
2 : bbbb

Thank you for your help again!




On Thu, 14 Oct 2021 at 06:24, David Carlisle d.p.carlisle@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> On Thu, 14 Oct 2021 at 11:05, Prady Prady prady.chin@xxxxxxxxx
> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> >
> > Thank you for the response,  Michael!
> >
> > But Oracle BPEL 2.0 does not support XSLT 3.0. It only supports XSLT 1.0
>
> It would help if you clarified your question as your expected result
> doesn't match the transformation you ask for.
>
> Is the input always of the form
>
> aaa#bbbb;ccc#ddd
>
> with one ; and two #  (as in the example you show) or can you have any
> number of ; and # and you want to delete any text between adjacent #
> and ; (as the title of the thread implies)?
>
> Especially with xslt1 which has no regex replace doing the first which
> doesn't require any searching and looping is significantly simpler,
> basically
>
> <xsl:value-of select="substring-before(.,'#')"/>
> <xsl:text>;</xsl:text>
> <xsl:value-of select="substring-before(substring-after(.,';'),'#')"/>
>
> will produce aaa;ccc  if . is the string above.
>
> David
>
>
> David
>
> >
> > Any help using XSLT 1.0 is greatly appreciated
> >
> > On Wed, 13 Oct 2021 at 13:43, Michael MC<ller-Hillebrand mmh@xxxxxxxxx <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> >>
> >> Hi Prady,
> >>
> >> Assuming you meant "string split by ;" I came up with this template
> doing the work:
> >>
> >>   <xsl:template match="Ip">
> >>     <xsl:variable name="entries" select="tokenize(text(), '\s*;\s*')"
> as="xs:string*"/>
> >>     <xsl:element name="nums" namespace="http://xmlns.ieee.org/V2";>
> >>       <xsl:value-of select="($entries ! substring-before(., '#')) =>
> string-join(';')" />
> >>     </xsl:element>
> >>   </xsl:template>
> >>
> >> It uses XSLT 3 features, because they are so great, and b frankly b
I
> am not motivated to do this using XSLT1. This will most probably involve a
> recursive template using substring-before and substring-after.
> >>
> >> - Michael
> >>
> >>
> >> Am 13.10.2021 um 17:32 schrieb Prady Prady prady.chin@xxxxxxxxx <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>:
> >>
> >> Team,
> >>
> >>
> >> Can somebody help me to replace string that is in between # and ; with
> blank. I need to include this is oracle bpel which only supports xslt 1.0
> >>
> >> From:
> >> <IpsCollection xmlns="http://xmlns.oracle.com/aa";>
> >> <Ips>
> >>   <Ip>q1#11.11.11.111;q2#22.22.22.22</Ip>
> >> </Ips>
> >>  </IpsCollection>
> >> To:
> >>  <v2:Ops xmlns:v2="http://xmlns.ieee.org/V2";>
> >> <v2:nums>q1;q2</v2:nums>
> >>  </v2:Ops>
> >>
> >>
> >> Thank you very much for your help!
> >>
> >>
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