RE: [xsl] catching the last node still satisfying a conditio

Subject: RE: [xsl] catching the last node still satisfying a condition
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Thu, 13 Sep 2001 15:12:26 +0100

> I've some difficulties in a XPath expression:
> In a <foos> list of <foo> i would like to catch:
> - the last one
> - having a <bar> child
> - up to a certain limit

Perhaps:

foos/foo[position() &lt; $limit][bar][last()]

(But your requirement is not entirely clear)

Mike Kay 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
Re: [xsl] catching the last node still satisfying a condition, (continued) Guillaume Rousse - Thu, 13 Sep 2001 16:30:51 +0200 David Carlisle - Thu, 13 Sep 2001 16:00:26 +0100 Michael Kay - Thu, 13 Sep 2001 15:34:31 +0100 Dimitar Peikov - Thu, 13 Sep 2001 17:51:27 +0300 Michael Kay - Thu, 13 Sep 2001 15:12:26 +0100 <= Guillaume Rousse - Thu, 13 Sep 2001 16:23:48 +0200 David Carlisle - Thu, 13 Sep 2001 15:52:07 +0100 Guillaume Rousse - Thu, 13 Sep 2001 17:38:54 +0200 Michael Kay - Thu, 13 Sep 2001 15:53:00 +0100

Current Thread

Re: [xsl] catching the last node still satisfying a condition, (continued)
- Michael Kay - Thu, 13 Sep 2001 15:12:26 +0100 <=
  - Guillaume Rousse - Thu, 13 Sep 2001 16:23:48 +0200
    - David Carlisle - Thu, 13 Sep 2001 15:52:07 +0100
    - Guillaume Rousse - Thu, 13 Sep 2001 17:38:54 +0200
    - Michael Kay - Thu, 13 Sep 2001 15:53:00 +0100

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