RE: [xsl] dynamic sorting

[Danny Guindi <Danny.Guindi@xxxxxxx>]

Thanks Max and Joerg for your replies.  I do, however, have a couple more
questions.

Max, the URLs you sent me show exactly what I want to do, but it doesn't
allow me to view the source, so I can see how JavaScript is called to
perform the sort.

Joerg, I still don't understand how parameters are passed between XML and
XSL?  Here is my simple test code, but I don't know how to make it sort.

XML
-----

<?xml version="1.0"?>

<root>
    <row>
        <name>test1</name>
        <age>20</age>
        <city>london</city>
        <country>great britain</country>
    </row>
    <row>
        <name>test2</name>
        <age>40</age>
        <city>new york</city>
        <country>united states</country>
    </row>
</root>

XSL
---

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:param name="sort">name</xsl:param>

<xsl:template match="root">
	<table border='1'>
		<tr>
		<th>Name</th>
		<th>Age</th>
		<th>City</th>
		<th>Country</th>
		</tr>
	    <xsl:apply-templates select="row">
    	    <xsl:sort select="*[name() = $sort]"/>
    	</xsl:apply-templates>
	</table>
</xsl:template>

<xsl:template match="row">
		<tr>
    	<td><xsl:value-of select="name"/></td>
    	<td><xsl:value-of select="age"/></td>
    	<td><xsl:value-of select="city"/></td>
    	<td><xsl:value-of select="country"/></td>
    	</tr>
</xsl:template>

</xsl:stylesheet>

Thanks again,

Danny

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list