[xsl] knowing the position of certain node

Subject: [xsl] knowing the position of certain node
From: "Jaime A Stuardo Bahamondes" <jstuardo@xxxxxxxxxxx>
Date: Tue, 6 Jan 2004 09:50:03 -0400
Hi all..

I have this sample XML:

<test>
  <row>
    <field1>this</field1>
  </row>
  <row>
    <field1>is</field1>
  </row>
  <row>
    <field1>a</field1>
    <field2>yes</field2>
  </row>
  <row>
    <field1>test</field1>
  </row>
</test>


If I use <xsl:value-of select="row[field2 = 'yes']" /> I get all the third "row" field values. How can I know the position of the found node? for example, in that case, I want 3 to be printed on screen, something like "position(row[field2 = 'yes'])"

Thanks
Jaime

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